10x-14x+3-19=8(2+x)-4x

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Solution for 10x-14x+3-19=8(2+x)-4x equation: 



10x-14x+3-19=8(2+x)-4x

We move all terms to the left:

10x-14x+3-19-(8(2+x)-4x)=0

We add all the numbers together, and all the variables

10x-14x-(8(x+2)-4x)+3-19=0

We add all the numbers together, and all the variables

-4x-(8(x+2)-4x)-16=0



We calculate terms in parentheses: -(8(x+2)-4x), so:

8(x+2)-4x

We add all the numbers together, and all the variables

-4x+8(x+2)

We multiply parentheses

-4x+8x+16

We add all the numbers together, and all the variables

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

-4x-4x-16-16=0

We add all the numbers together, and all the variables

-8x-32=0

We move all terms containing x to the left, all other terms to the right

-8x=32

x=32/-8

x=-4

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