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10x-(x-18)=2x-(-6+x)
We move all terms to the left:
10x-(x-18)-(2x-(-6+x))=0
We add all the numbers together, and all the variables
10x-(x-18)-(2x-(x-6))=0
We get rid of parentheses
10x-x-(2x-(x-6))+18=0
We calculate terms in parentheses: -(2x-(x-6)), so:We add all the numbers together, and all the variables
2x-(x-6)
We get rid of parentheses
2x-x+6
We add all the numbers together, and all the variables
x+6
Back to the equation:
-(x+6)
9x-(x+6)+18=0
We get rid of parentheses
9x-x-6+18=0
We add all the numbers together, and all the variables
8x+12=0
We move all terms containing x to the left, all other terms to the right
8x=-12
x=-12/8
x=-1+1/2
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