10x-(3x+10)=9(x-2)

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Solution for 10x-(3x+10)=9(x-2) equation:



10x-(3x+10)=9(x-2)
We move all terms to the left:
10x-(3x+10)-(9(x-2))=0
We get rid of parentheses
10x-3x-(9(x-2))-10=0
We calculate terms in parentheses: -(9(x-2)), so:
9(x-2)
We multiply parentheses
9x-18
Back to the equation:
-(9x-18)
We add all the numbers together, and all the variables
7x-(9x-18)-10=0
We get rid of parentheses
7x-9x+18-10=0
We add all the numbers together, and all the variables
-2x+8=0
We move all terms containing x to the left, all other terms to the right
-2x=-8
x=-8/-2
x=+4

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