10x+40=4x-(-12)

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Solution for 10x+40=4x-(-12) equation: 



10x+40=4x-(-12)

We move all terms to the left:

10x+40-(4x-(-12))=0



We calculate terms in parentheses: -(4x-(-12)), so:

4x-(-12)

We add all the numbers together, and all the variables

4x+12

Back to the equation:

-(4x+12)



We get rid of parentheses

10x-4x-12+40=0

We add all the numbers together, and all the variables

6x+28=0

We move all terms containing x to the left, all other terms to the right

6x=-28

x=-28/6

x=-4+2/3

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