10x+4-8x=2(x+2)

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Solution for 10x+4-8x=2(x+2) equation: 



10x+4-8x=2(x+2)

We move all terms to the left:

10x+4-8x-(2(x+2))=0

We add all the numbers together, and all the variables

2x-(2(x+2))+4=0



We calculate terms in parentheses: -(2(x+2)), so:

2(x+2)

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)



We get rid of parentheses

2x-2x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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