10x+4(4x-3)=4(6x+4)+4

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Solution for 10x+4(4x-3)=4(6x+4)+4 equation: 



10x+4(4x-3)=4(6x+4)+4

We move all terms to the left:

10x+4(4x-3)-(4(6x+4)+4)=0

We multiply parentheses

10x+16x-(4(6x+4)+4)-12=0



We calculate terms in parentheses: -(4(6x+4)+4), so:

4(6x+4)+4

We multiply parentheses

24x+16+4

We add all the numbers together, and all the variables

24x+20

Back to the equation:

-(24x+20)



We add all the numbers together, and all the variables

26x-(24x+20)-12=0

We get rid of parentheses

26x-24x-20-12=0

We add all the numbers together, and all the variables

2x-32=0

We move all terms containing x to the left, all other terms to the right

2x=32

x=32/2

x=16

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