10x+3/4x-8=5x+2/2x-4

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Solution for 10x+3/4x-8=5x+2/2x-4 equation: 



10x+3/4x-8=5x+2/2x-4

We move all terms to the left:

10x+3/4x-8-(5x+2/2x-4)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: 2x-4)!=0

x∈R



We get rid of parentheses

10x+3/4x-5x-2/2x+4-8=0

We calculate fractions


10x-5x+6x/8x^2+(-8x)/8x^2+4-8=0

We add all the numbers together, and all the variables

5x+6x/8x^2+(-8x)/8x^2-4=0

We multiply all the terms by the denominator


5x*8x^2+6x+(-8x)-4*8x^2=0

We add all the numbers together, and all the variables

6x+5x*8x^2+(-8x)-4*8x^2=0

Wy multiply elements

40x^3-32x^2+6x+(-8x)=0

We get rid of parentheses

40x^3-32x^2+6x-8x=0

We do not support expression: x^3

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