10x+3(x-4)=10(x-5)-3x

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Solution for 10x+3(x-4)=10(x-5)-3x equation: 



10x+3(x-4)=10(x-5)-3x

We move all terms to the left:

10x+3(x-4)-(10(x-5)-3x)=0

We multiply parentheses

10x+3x-(10(x-5)-3x)-12=0



We calculate terms in parentheses: -(10(x-5)-3x), so:

10(x-5)-3x

We add all the numbers together, and all the variables

-3x+10(x-5)

We multiply parentheses

-3x+10x-50

We add all the numbers together, and all the variables

7x-50

Back to the equation:

-(7x-50)



We add all the numbers together, and all the variables

13x-(7x-50)-12=0

We get rid of parentheses

13x-7x+50-12=0

We add all the numbers together, and all the variables

6x+38=0

We move all terms containing x to the left, all other terms to the right

6x=-38

x=-38/6

x=-6+1/3

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