10x+28=2(3x+12)

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Solution for 10x+28=2(3x+12) equation: 



10x+28=2(3x+12)

We move all terms to the left:

10x+28-(2(3x+12))=0



We calculate terms in parentheses: -(2(3x+12)), so:

2(3x+12)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

10x-6x-24+28=0

We add all the numbers together, and all the variables

4x+4=0

We move all terms containing x to the left, all other terms to the right

4x=-4

x=-4/4

x=-1

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