10x+20=(9x-8)+40

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Solution for 10x+20=(9x-8)+40 equation: 



10x+20=(9x-8)+40

We move all terms to the left:

10x+20-((9x-8)+40)=0



We calculate terms in parentheses: -((9x-8)+40), so:

(9x-8)+40

We get rid of parentheses

9x-8+40

We add all the numbers together, and all the variables

9x+32

Back to the equation:

-(9x+32)



We get rid of parentheses

10x-9x-32+20=0

We add all the numbers together, and all the variables

x-12=0

We move all terms containing x to the left, all other terms to the right

x=12

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