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10x+15/20x-8=0
Domain of the equation: 20x!=0We multiply all the terms by the denominator
x!=0/20
x!=0
x∈R
10x*20x-8*20x+15=0
Wy multiply elements
200x^2-160x+15=0
a = 200; b = -160; c = +15;
Δ = b2-4ac
Δ = -1602-4·200·15
Δ = 13600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13600}=\sqrt{400*34}=\sqrt{400}*\sqrt{34}=20\sqrt{34}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-20\sqrt{34}}{2*200}=\frac{160-20\sqrt{34}}{400} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+20\sqrt{34}}{2*200}=\frac{160+20\sqrt{34}}{400} $
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