10x+10=2(3+5x)+4(4+5x)

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Solution for 10x+10=2(3+5x)+4(4+5x) equation: 



10x+10=2(3+5x)+4(4+5x)

We move all terms to the left:

10x+10-(2(3+5x)+4(4+5x))=0

We add all the numbers together, and all the variables

10x-(2(5x+3)+4(5x+4))+10=0



We calculate terms in parentheses: -(2(5x+3)+4(5x+4)), so:

2(5x+3)+4(5x+4)

We multiply parentheses

10x+20x+6+16

We add all the numbers together, and all the variables

30x+22

Back to the equation:

-(30x+22)



We get rid of parentheses

10x-30x-22+10=0

We add all the numbers together, and all the variables

-20x-12=0

We move all terms containing x to the left, all other terms to the right

-20x=12

x=12/-20

x=-3/5

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