10x*4x=18.13

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Solution for 10x*4x=18.13 equation:



10x*4x=18.13
We move all terms to the left:
10x*4x-(18.13)=0
We add all the numbers together, and all the variables
10x*4x-18.13=0
Wy multiply elements
40x^2-18.13=0
a = 40; b = 0; c = -18.13;
Δ = b2-4ac
Δ = 02-4·40·(-18.13)
Δ = 2900.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2900.8}}{2*40}=\frac{0-\sqrt{2900.8}}{80} =-\frac{\sqrt{}}{80} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2900.8}}{2*40}=\frac{0+\sqrt{2900.8}}{80} =\frac{\sqrt{}}{80} $

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