10x(x-5)=2(5x-1)(x-6)

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Solution for 10x(x-5)=2(5x-1)(x-6) equation: 



10x(x-5)=2(5x-1)(x-6)

We move all terms to the left:

10x(x-5)-(2(5x-1)(x-6))=0

We multiply parentheses

10x^2-50x-(2(5x-1)(x-6))=0

We multiply parentheses ..

10x^2-(2(+5x^2-30x-1x+6))-50x=0



We calculate terms in parentheses: -(2(+5x^2-30x-1x+6)), so:

2(+5x^2-30x-1x+6)

We multiply parentheses

10x^2-60x-2x+12

We add all the numbers together, and all the variables

10x^2-62x+12

Back to the equation:

-(10x^2-62x+12)



We add all the numbers together, and all the variables

10x^2-50x-(10x^2-62x+12)=0

We get rid of parentheses

10x^2-10x^2-50x+62x-12=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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