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10x(x-11)-10=23x-211
We move all terms to the left:
10x(x-11)-10-(23x-211)=0
We multiply parentheses
10x^2-110x-(23x-211)-10=0
We get rid of parentheses
10x^2-110x-23x+211-10=0
We add all the numbers together, and all the variables
10x^2-133x+201=0
a = 10; b = -133; c = +201;
Δ = b2-4ac
Δ = -1332-4·10·201
Δ = 9649
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-133)-\sqrt{9649}}{2*10}=\frac{133-\sqrt{9649}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-133)+\sqrt{9649}}{2*10}=\frac{133+\sqrt{9649}}{20} $
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