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10x(-2x-9)=-3(25-4x)
We move all terms to the left:
10x(-2x-9)-(-3(25-4x))=0
We add all the numbers together, and all the variables
10x(-2x-9)-(-3(-4x+25))=0
We multiply parentheses
-20x^2-90x-(-3(-4x+25))=0
We calculate terms in parentheses: -(-3(-4x+25)), so:We get rid of parentheses
-3(-4x+25)
We multiply parentheses
12x-75
Back to the equation:
-(12x-75)
-20x^2-90x-12x+75=0
We add all the numbers together, and all the variables
-20x^2-102x+75=0
a = -20; b = -102; c = +75;
Δ = b2-4ac
Δ = -1022-4·(-20)·75
Δ = 16404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{16404}=\sqrt{4*4101}=\sqrt{4}*\sqrt{4101}=2\sqrt{4101}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-102)-2\sqrt{4101}}{2*-20}=\frac{102-2\sqrt{4101}}{-40} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-102)+2\sqrt{4101}}{2*-20}=\frac{102+2\sqrt{4101}}{-40} $
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