10v-3(2v-9)=9(v-1)+1

Solution for 10v-3(2v-9)=9(v-1)+1 equation:

10v-3(2v-9)=9(v-1)+1

We move all terms to the left:

10v-3(2v-9)-(9(v-1)+1)=0

We multiply parentheses

10v-6v-(9(v-1)+1)+27=0


We calculate terms in parentheses: -(9(v-1)+1), so:

9(v-1)+1

We multiply parentheses

9v-9+1

We add all the numbers together, and all the variables

9v-8

Back to the equation:

-(9v-8)


We add all the numbers together, and all the variables

4v-(9v-8)+27=0

We get rid of parentheses

4v-9v+8+27=0

We add all the numbers together, and all the variables

-5v+35=0

We move all terms containing v to the left, all other terms to the right

-5v=-35

v=-35/-5

v=+7