10t/8t=30/(8t-20)

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Solution for 10t/8t=30/(8t-20) equation:



10t/8t=30/(8t-20)
We move all terms to the left:
10t/8t-(30/(8t-20))=0
Domain of the equation: 8t!=0
t!=0/8
t!=0
t∈R
Domain of the equation: (8t-20))!=0
t∈R
We calculate fractions
(-120t^2)/(-96t^2)+(-(30*8t)/(-96t^2)=0
We calculate terms in parentheses: +(-(30*8t)/(-96t^2), so:
-(30*8t)/(-96t^2
We add all the numbers together, and all the variables
-(+30*8t)/(-96t^2
We multiply all the terms by the denominator
-(+30*8t)
We get rid of parentheses
-30*8t
Wy multiply elements
-240t
Back to the equation:
+(-240t)
We get rid of parentheses
(-120t^2)/(-96t^2)-240t=0
We multiply all the terms by the denominator
(-120t^2)-240t*(-96t^2)=0
We multiply parentheses
(-120t^2)+23040t^3=0
We get rid of parentheses
-120t^2+23040t^3=0
We do not support etpression: t^3

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