10t-2-4t=5t+8(2t-3)

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Solution for 10t-2-4t=5t+8(2t-3) equation: 



10t-2-4t=5t+8(2t-3)

We move all terms to the left:

10t-2-4t-(5t+8(2t-3))=0

We add all the numbers together, and all the variables

6t-(5t+8(2t-3))-2=0



We calculate terms in parentheses: -(5t+8(2t-3)), so:

5t+8(2t-3)

We multiply parentheses

5t+16t-24

We add all the numbers together, and all the variables

21t-24

Back to the equation:

-(21t-24)



We get rid of parentheses

6t-21t+24-2=0

We add all the numbers together, and all the variables

-15t+22=0

We move all terms containing t to the left, all other terms to the right

-15t=-22

t=-22/-15

t=1+7/15

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