10t+4-2t=2-2(t-4)

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Solution for 10t+4-2t=2-2(t-4) equation: 



10t+4-2t=2-2(t-4)

We move all terms to the left:

10t+4-2t-(2-2(t-4))=0

We add all the numbers together, and all the variables

8t-(2-2(t-4))+4=0



We calculate terms in parentheses: -(2-2(t-4)), so:

2-2(t-4)

determiningTheFunctionDomain
-2(t-4)+2

We multiply parentheses

-2t+8+2

We add all the numbers together, and all the variables

-2t+10

Back to the equation:

-(-2t+10)



We get rid of parentheses

8t+2t-10+4=0

We add all the numbers together, and all the variables

10t-6=0

We move all terms containing t to the left, all other terms to the right

10t=6

t=6/10

t=3/5

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