10t+3t+5=2(t-3)

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Solution for 10t+3t+5=2(t-3) equation: 



10t+3t+5=2(t-3)

We move all terms to the left:

10t+3t+5-(2(t-3))=0

We add all the numbers together, and all the variables

13t-(2(t-3))+5=0



We calculate terms in parentheses: -(2(t-3)), so:

2(t-3)

We multiply parentheses

2t-6

Back to the equation:

-(2t-6)



We get rid of parentheses

13t-2t+6+5=0

We add all the numbers together, and all the variables

11t+11=0

We move all terms containing t to the left, all other terms to the right

11t=-11

t=-11/11

t=-1

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