10sin(2(x-3))+5=4

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Solution for 10sin(2(x-3))+5=4 equation:


Simplifying
10sin(2(x + -3)) + 5 = 4

Reorder the terms:
10ins(2(-3 + x)) + 5 = 4
10ins((-3 * 2 + x * 2)) + 5 = 4
10ins((-6 + 2x)) + 5 = 4
(-6 * 10ins + 2x * 10ins) + 5 = 4
(-60ins + 20insx) + 5 = 4

Reorder the terms:
5 + -60ins + 20insx = 4

Solving
5 + -60ins + 20insx = 4

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + -60ins + -5 + 20insx = 4 + -5

Reorder the terms:
5 + -5 + -60ins + 20insx = 4 + -5

Combine like terms: 5 + -5 = 0
0 + -60ins + 20insx = 4 + -5
-60ins + 20insx = 4 + -5

Combine like terms: 4 + -5 = -1
-60ins + 20insx = -1

Reorder the terms:
1 + -60ins + 20insx = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -60ins + 20insx = 0

The solution to this equation could not be determined.

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