10q-z(2q-5)=29

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Solution for 10q-z(2q-5)=29 equation:


Simplifying
10q + -1z(2q + -5) = 29

Reorder the terms:
10q + -1z(-5 + 2q) = 29
10q + (-5 * -1z + 2q * -1z) = 29

Reorder the terms:
10q + (-2qz + 5z) = 29
10q + (-2qz + 5z) = 29

Solving
10q + -2qz + 5z = 29

Solving for variable 'q'.

Move all terms containing q to the left, all other terms to the right.

Add '-5z' to each side of the equation.
10q + -2qz + 5z + -5z = 29 + -5z

Combine like terms: 5z + -5z = 0
10q + -2qz + 0 = 29 + -5z
10q + -2qz = 29 + -5z

Reorder the terms:
-29 + 10q + -2qz + 5z = 29 + -5z + -29 + 5z

Reorder the terms:
-29 + 10q + -2qz + 5z = 29 + -29 + -5z + 5z

Combine like terms: 29 + -29 = 0
-29 + 10q + -2qz + 5z = 0 + -5z + 5z
-29 + 10q + -2qz + 5z = -5z + 5z

Combine like terms: -5z + 5z = 0
-29 + 10q + -2qz + 5z = 0

The solution to this equation could not be determined.

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