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10q+3q=2(q-3)
We move all terms to the left:
10q+3q-(2(q-3))=0
We add all the numbers together, and all the variables
13q-(2(q-3))=0
We calculate terms in parentheses: -(2(q-3)), so:We get rid of parentheses
2(q-3)
We multiply parentheses
2q-6
Back to the equation:
-(2q-6)
13q-2q+6=0
We add all the numbers together, and all the variables
11q+6=0
We move all terms containing q to the left, all other terms to the right
11q=-6
q=-6/11
q=-6/11
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