10p+9-11-p=-2(2p+4p)-3(2p-2)

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Solution for 10p+9-11-p=-2(2p+4p)-3(2p-2) equation: 



10p+9-11-p=-2(2p+4p)-3(2p-2)

We move all terms to the left:

10p+9-11-p-(-2(2p+4p)-3(2p-2))=0

We add all the numbers together, and all the variables

10p-p-(-2(+6p)-3(2p-2))+9-11=0

We add all the numbers together, and all the variables

9p-(-2(+6p)-3(2p-2))-2=0



We calculate terms in parentheses: -(-2(+6p)-3(2p-2)), so:

-2(+6p)-3(2p-2)

We multiply parentheses

-12p-6p+6

We add all the numbers together, and all the variables

-18p+6

Back to the equation:

-(-18p+6)



We get rid of parentheses

9p+18p-6-2=0

We add all the numbers together, and all the variables

27p-8=0

We move all terms containing p to the left, all other terms to the right

27p=8

p=8/27

p=8/27

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