10p+9-11-p=-2(-p+4)-3(2p-2)

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Solution for 10p+9-11-p=-2(-p+4)-3(2p-2) equation: 



10p+9-11-p=-2(-p+4)-3(2p-2)

We move all terms to the left:

10p+9-11-p-(-2(-p+4)-3(2p-2))=0

We add all the numbers together, and all the variables

10p-p-(-2(-1p+4)-3(2p-2))+9-11=0

We add all the numbers together, and all the variables

9p-(-2(-1p+4)-3(2p-2))-2=0



We calculate terms in parentheses: -(-2(-1p+4)-3(2p-2)), so:

-2(-1p+4)-3(2p-2)

We multiply parentheses

2p-6p-8+6

We add all the numbers together, and all the variables

-4p-2

Back to the equation:

-(-4p-2)



We get rid of parentheses

9p+4p+2-2=0

We add all the numbers together, and all the variables

13p=0

p=0/13

p=0

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