10n+3(2+2n)=-6(n-4)

Solution for 10n+3(2+2n)=-6(n-4) equation:

10n+3(2+2n)=-6(n-4)

We move all terms to the left:

10n+3(2+2n)-(-6(n-4))=0

We add all the numbers together, and all the variables

10n+3(2n+2)-(-6(n-4))=0

We multiply parentheses

10n+6n-(-6(n-4))+6=0


We calculate terms in parentheses: -(-6(n-4)), so:

-6(n-4)

We multiply parentheses

-6n+24

Back to the equation:

-(-6n+24)


We add all the numbers together, and all the variables

16n-(-6n+24)+6=0

We get rid of parentheses

16n+6n-24+6=0

We add all the numbers together, and all the variables

22n-18=0

We move all terms containing n to the left, all other terms to the right

22n=18

n=18/22

n=9/11