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10n(5-n)-1=29
We move all terms to the left:
10n(5-n)-1-(29)=0
We add all the numbers together, and all the variables
10n(-1n+5)-1-29=0
We add all the numbers together, and all the variables
10n(-1n+5)-30=0
We multiply parentheses
-10n^2+50n-30=0
a = -10; b = 50; c = -30;
Δ = b2-4ac
Δ = 502-4·(-10)·(-30)
Δ = 1300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1300}=\sqrt{100*13}=\sqrt{100}*\sqrt{13}=10\sqrt{13}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-10\sqrt{13}}{2*-10}=\frac{-50-10\sqrt{13}}{-20} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+10\sqrt{13}}{2*-10}=\frac{-50+10\sqrt{13}}{-20} $
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