10k-8k(3-k)=-6

Solution for 10k-8k(3-k)=-6 equation:

10k-8k(3-k)=-6

We move all terms to the left:

10k-8k(3-k)-(-6)=0

We add all the numbers together, and all the variables

10k-8k(-1k+3)-(-6)=0

We add all the numbers together, and all the variables

10k-8k(-1k+3)+6=0

We multiply parentheses

8k^2+10k-24k+6=0

We add all the numbers together, and all the variables

8k^2-14k+6=0

a = 8; b = -14; c = +6;
Δ = b2-4ac
Δ = -142-4·8·6
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2}{2*8}=\frac{12}{16}
=3/4
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2}{2*8}=\frac{16}{16}
=1
$