10j-6(2j-1)=-2(j-3)

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Solution for 10j-6(2j-1)=-2(j-3) equation: 



10j-6(2j-1)=-2(j-3)

We move all terms to the left:

10j-6(2j-1)-(-2(j-3))=0

We multiply parentheses

10j-12j-(-2(j-3))+6=0



We calculate terms in parentheses: -(-2(j-3)), so:

-2(j-3)

We multiply parentheses

-2j+6

Back to the equation:

-(-2j+6)



We add all the numbers together, and all the variables

-2j-(-2j+6)+6=0

We get rid of parentheses

-2j+2j-6+6=0

We add all the numbers together, and all the variables

=0

j=0/1

j=0

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