10i/(3-i)=10i/3-i

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Solution for 10i/(3-i)=10i/3-i equation:


D( i )

3-i = 0

3-i = 0

3-i = 0

3-i = 0 // - 3

-i = -3 // * -1

i = 3

i in (-oo:3) U (3:+oo)

(10*i)/(3-i) = (10*i)/3-i // - (10*i)/3-i

(10*i)/(3-i)-((10*i)/3)+i = 0

(10*i)/(3-i)+(-10/3)*i+i = 0

(10*i)/(3-i)+(-10*i)/3+i = 0

(3*10*i)/(3*(3-i))+(-10*i*(3-i))/(3*(3-i))+(3*i*(3-i))/(3*(3-i)) = 0

3*i*(3-i)-10*i*(3-i)+3*10*i = 0

10*i^2-3*i^2+9*i = 0

7*i^2+9*i = 0

7*i^2+9*i = 0

i*(7*i+9) = 0

7*i+9 = 0 // - 9

7*i = -9 // : 7

i = -9/7

i*(i+9/7) = 0

(i*(i+9/7))/(3*(3-i)) = 0

(i*(i+9/7))/(3*(3-i)) = 0 // * 3*(3-i)

i*(i+9/7) = 0

( i+9/7 )

i+9/7 = 0 // - 9/7

i = -9/7

( i )

i = 0

i in { -9/7, 0 }

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