10d-8+12-4d+2=4(d-6)

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Solution for 10d-8+12-4d+2=4(d-6) equation: 



10d-8+12-4d+2=4(d-6)

We move all terms to the left:

10d-8+12-4d+2-(4(d-6))=0

We add all the numbers together, and all the variables

6d-(4(d-6))+6=0



We calculate terms in parentheses: -(4(d-6)), so:

4(d-6)

We multiply parentheses

4d-24

Back to the equation:

-(4d-24)



We get rid of parentheses

6d-4d+24+6=0

We add all the numbers together, and all the variables

2d+30=0

We move all terms containing d to the left, all other terms to the right

2d=-30

d=-30/2

d=-15

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