10d+4=6(4/3d+2)

Solution for 10d+4=6(4/3d+2) equation:

10d+4=6(4/3d+2)

We move all terms to the left:

10d+4-(6(4/3d+2))=0


Domain of the equation: 3d+2))!=0

d∈R


We multiply all the terms by the denominator


10d*3d+4*3d+2))-(6(4+2))=0

We add all the numbers together, and all the variables

10d*3d+4*3d+2))-(66)=0

We add all the numbers together, and all the variables

10d*3d+4*3d=0

Wy multiply elements

30d^2+12d=0

a = 30; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·30·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*30}=\frac{-24}{60}
=-2/5
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*30}=\frac{0}{60}
=0
$