10c+2+-12c+4c=20

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Solution for 10c+2+-12c+4c=20 equation: 



10c+2+-12c+4c=20

We move all terms to the left:

10c+2+-12c+4c-(20)=0

determiningTheFunctionDomain
10c-12c+4c+2-20+=0

We add all the numbers together, and all the variables

2c=0

c=0/2

c=0

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