10b/5b=5b+3b+2b

Solution for 10b/5b=5b+3b+2b equation:

10b/5b=5b+3b+2b

We move all terms to the left:

10b/5b-(5b+3b+2b)=0


Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R


We add all the numbers together, and all the variables

10b/5b-(+10b)=0

We get rid of parentheses

10b/5b-10b=0

We multiply all the terms by the denominator


10b-10b*5b=0

Wy multiply elements

-50b^2+10b=0

a = -50; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·(-50)·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*-50}=\frac{-20}{-100}
=1/5
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*-50}=\frac{0}{-100}
=0
$