10b+4b2=-0

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Solution for 10b+4b2=-0 equation:



10b+4b^2=-0
a = 4; b = 10; c = 0;
Δ = b2-4ac
Δ = 102-4·4·0
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-10}{2*4}=\frac{-20}{8} =-2+1/2 $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+10}{2*4}=\frac{0}{8} =0 $

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