10a=4(a-7)+5a

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Solution for 10a=4(a-7)+5a equation: 



10a=4(a-7)+5a

We move all terms to the left:

10a-(4(a-7)+5a)=0



We calculate terms in parentheses: -(4(a-7)+5a), so:

4(a-7)+5a

We add all the numbers together, and all the variables

5a+4(a-7)

We multiply parentheses

5a+4a-28

We add all the numbers together, and all the variables

9a-28

Back to the equation:

-(9a-28)



We get rid of parentheses

10a-9a+28=0

We add all the numbers together, and all the variables

a+28=0

We move all terms containing a to the left, all other terms to the right

a=-28

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