10a2=6+6a

Solution for 10a2=6+6a equation:

10a^2=6+6a

We move all terms to the left:

10a^2-(6+6a)=0

We add all the numbers together, and all the variables

10a^2-(6a+6)=0

We get rid of parentheses

10a^2-6a-6=0

a = 10; b = -6; c = -6;
Δ = b2-4ac
Δ = -62-4·10·(-6)
Δ = 276
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{276}=\sqrt{4*69}=\sqrt{4}*\sqrt{69}=2\sqrt{69}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{69}}{2*10}=\frac{6-2\sqrt{69}}{20}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{69}}{2*10}=\frac{6+2\sqrt{69}}{20}
$