10a2+37a-36=0

Solution for 10a2+37a-36=0 equation:

10a^2+37a-36=0

a = 10; b = 37; c = -36;
Δ = b2-4ac
Δ = 372-4·10·(-36)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-53}{2*10}=\frac{-90}{20}
=-4+1/2
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+53}{2*10}=\frac{16}{20}
=4/5
$