10a-5+5a=5(3a-2)+5

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Solution for 10a-5+5a=5(3a-2)+5 equation: 



10a-5+5a=5(3a-2)+5

We move all terms to the left:

10a-5+5a-(5(3a-2)+5)=0

We add all the numbers together, and all the variables

15a-(5(3a-2)+5)-5=0



We calculate terms in parentheses: -(5(3a-2)+5), so:

5(3a-2)+5

We multiply parentheses

15a-10+5

We add all the numbers together, and all the variables

15a-5

Back to the equation:

-(15a-5)



We get rid of parentheses

15a-15a+5-5=0

We add all the numbers together, and all the variables

=0

a=0/1

a=0

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