10a+4=3(a-1)=14

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Solution for 10a+4=3(a-1)=14 equation: 



10a+4=3(a-1)=14

We move all terms to the left:

10a+4-(3(a-1))=0



We calculate terms in parentheses: -(3(a-1)), so:

3(a-1)

We multiply parentheses

3a-3

Back to the equation:

-(3a-3)



We get rid of parentheses

10a-3a+3+4=0

We add all the numbers together, and all the variables

7a+7=0

We move all terms containing a to the left, all other terms to the right

7a=-7

a=-7/7

a=-1

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