10=b(b-9)

Solution for 10=b(b-9) equation:

Simplifying
10 = b(b + -9)

Reorder the terms:
10 = b(-9 + b)
10 = (-9 * b + b * b)
10 = (-9b + b2)

Solving
10 = -9b + b2

Solving for variable 'b'.

Reorder the terms:
10 + 9b + -1b2 = -9b + 9b + b2 + -1b2

Combine like terms: -9b + 9b = 0
10 + 9b + -1b2 = 0 + b2 + -1b2
10 + 9b + -1b2 = b2 + -1b2

Combine like terms: b2 + -1b2 = 0
10 + 9b + -1b2 = 0

Factor a trinomial.
(10 + -1b)(1 + b) = 0

Subproblem 1
Set the factor '(10 + -1b)' equal to zero and attempt to solve:

Simplifying
10 + -1b = 0

Solving
10 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1b = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1b = 0 + -10
-1b = 0 + -10

Combine like terms: 0 + -10 = -10
-1b = -10

Divide each side by '-1'.
b = 10

Simplifying
b = 10
Subproblem 2
Set the factor '(1 + b)' equal to zero and attempt to solve:

Simplifying
1 + b = 0

Solving
1 + b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + b = 0 + -1
b = 0 + -1

Combine like terms: 0 + -1 = -1
b = -1

Simplifying
b = -1
Solution
b = {10, -1}