10=b(2/3)=

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Solution for 10=b(2/3)= equation: 


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a+b+c;a-b-(2*c);a+b+4*c

{root[2][544]}

857.96 = 1.1*21.4*x*(628-(0.5*x))

(X^1)/3-(2*x^2)-6 = 0

a+b+c;a-b-(2*c);a-(12*a)+b+4*c

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