10=5-2(x+3)

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Solution for 10=5-2(x+3) equation: 



10=5-2(x+3)

We move all terms to the left:

10-(5-2(x+3))=0



We calculate terms in parentheses: -(5-2(x+3)), so:

5-2(x+3)

determiningTheFunctionDomain
-2(x+3)+5

We multiply parentheses

-2x-6+5

We add all the numbers together, and all the variables

-2x-1

Back to the equation:

-(-2x-1)



We get rid of parentheses

2x+1+10=0

We add all the numbers together, and all the variables

2x+11=0

We move all terms containing x to the left, all other terms to the right

2x=-11

x=-11/2

x=-5+1/2

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