10=4+3+(t+2)

Solution for 10=4+3+(t+2) equation:

10=4+3+(t+2)

We move all terms to the left:

10-(4+3+(t+2))=0


We calculate terms in parentheses: -(4+3+(t+2)), so:

4+3+(t+2)

determiningTheFunctionDomain
(t+2)+4+3

We add all the numbers together, and all the variables

(t+2)+7

We get rid of parentheses

t+2+7

We add all the numbers together, and all the variables

t+9

Back to the equation:

-(t+9)


We get rid of parentheses

-t-9+10=0

We add all the numbers together, and all the variables

-1t+1=0

We move all terms containing t to the left, all other terms to the right

-t=-1

t=-1/-1

t=1