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10=4+3(b+2)
We move all terms to the left:
10-(4+3(b+2))=0
We calculate terms in parentheses: -(4+3(b+2)), so:We get rid of parentheses
4+3(b+2)
determiningTheFunctionDomain 3(b+2)+4
We multiply parentheses
3b+6+4
We add all the numbers together, and all the variables
3b+10
Back to the equation:
-(3b+10)
-3b-10+10=0
We add all the numbers together, and all the variables
-3b=0
b=0/-3
b=0
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