10=3x-19/2

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Solution for 10=3x-19/2 equation: 



10=3x-19/2

We move all terms to the left:

10-(3x-19/2)=0

We add all the numbers together, and all the variables

-(+3x-19/2)+10=0

We get rid of parentheses

-3x+10+19/2=0

We multiply all the terms by the denominator


-3x*2+19+10*2=0

We add all the numbers together, and all the variables

-3x*2+39=0

Wy multiply elements

-6x+39=0

We move all terms containing x to the left, all other terms to the right

-6x=-39

x=-39/-6

x=6+1/2

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