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10=3x(x-1)-8
We move all terms to the left:
10-(3x(x-1)-8)=0
We calculate terms in parentheses: -(3x(x-1)-8), so:We get rid of parentheses
3x(x-1)-8
We multiply parentheses
3x^2-3x-8
Back to the equation:
-(3x^2-3x-8)
-3x^2+3x+8+10=0
We add all the numbers together, and all the variables
-3x^2+3x+18=0
a = -3; b = 3; c = +18;
Δ = b2-4ac
Δ = 32-4·(-3)·18
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{225}=15$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-15}{2*-3}=\frac{-18}{-6} =+3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+15}{2*-3}=\frac{12}{-6} =-2 $
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