10=2x/(0.8-x)2

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Solution for 10=2x/(0.8-x)2 equation: 



10=2x/(0.8-x)2

We move all terms to the left:

10-(2x/(0.8-x)2)=0



Domain of the equation: (0.8-x)2)!=0

We move all terms containing x to the left, all other terms to the right

-x)2!=-0.8

x!=-0.8/1

x!=-0.8

x∈R



We add all the numbers together, and all the variables

-(2x/(-1x+0.8)2)+10=0

We multiply all the terms by the denominator


-(2x+10*(-1x+0.8)2)=0



We calculate terms in parentheses: -(2x+10*(-1x+0.8)2), so:

2x+10*(-1x+0.8)2

We multiply parentheses

2x-20x+16

We add all the numbers together, and all the variables

-18x+16

Back to the equation:

-(-18x+16)



We get rid of parentheses

18x-16=0

We move all terms containing x to the left, all other terms to the right

18x=16

x=16/18

x=8/9

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