10=2x-7(x+5)(x+4)

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Solution for 10=2x-7(x+5)(x+4) equation: 



10=2x-7(x+5)(x+4)

We move all terms to the left:

10-(2x-7(x+5)(x+4))=0

We multiply parentheses ..

-(2x-7(+x^2+4x+5x+20))+10=0



We calculate terms in parentheses: -(2x-7(+x^2+4x+5x+20)), so:

2x-7(+x^2+4x+5x+20)

determiningTheFunctionDomain
-7(+x^2+4x+5x+20)+2x

We multiply parentheses

-7x^2-28x-35x+2x-140

We add all the numbers together, and all the variables

-7x^2-61x-140

Back to the equation:

-(-7x^2-61x-140)



We get rid of parentheses

7x^2+61x+140+10=0

We add all the numbers together, and all the variables

7x^2+61x+150=0

a = 7; b = 61; c = +150;
Δ = b2-4ac
Δ = 612-4·7·150
Δ = -479
Delta is less than zero, so there is no solution for the equation

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